Likewise we combine (D) and (E), or one day ago (–1) and three days ago (–3), to get –4, or four days ago. If (A) is one day ago (–1) and (B) is in three days time (+ 3), when we combine (A) and (B) we get an outcome of –1 + 3 = + 2, or in two days time. (E) when two days after this day was a day ago, in other words, three days ago. (D) when the day after this day was today, in other words, one day ago. (C) we can rephrase this as ‘today will be as far from Friday as today was’, in other words, (A) and (B) are as far from Friday as (D) and (E). (B) when two days ago is a day from now, in other words, in three days time. (A) when the day after this day is today, in other words, one day ago. (E) when the day after to-morrow was yesterday (C) yesterday will be as far from Thursday as yesterday was (B) when the day before yesterday is to-morrow If this is the case, the day must be Sunday. So, the section states that the day in question is when the day three days before and three days after that day are equidistant from Sunday. (C) when a day ago was in two days’ time. (B) is saying that (A) and (C) are equidistant from Sunday
(A) when two days before this day is one day from now. (C) when the day after to-morrow is yesterday (B) to‑day was as far from Sunday as to-day will be (A) w hen the day before yesterday was to-morrow Y is “w hen to-morrow will be to-day when the day before yesterday is to-morrow yesterday will be as far from Thursday as yesterday was when to-morrow was to-day when the day after to-morrow was yesterday” X is “ when the day before yesterday was to-morrow to‑day was as far from Sunday as to-day will be when the day after to-morrow is yesterday” The opening sentence is saying: “The chicken was twice as old on X as it was on Y”, where both X and Y refer to days and where: The chicken was twice as old when when the day before yesterday was to-morrow to‑day was as far from Sunday as to-day will be when the day after to-morrow is yesterday as it was when when to-morrow will be to-day when the day before yesterday is to-morrow yesterday will be as far from Thursday as yesterday was when to-morrow was to-day when the day after to-morrow was yesterday. (The original question that asks what is 3/7 chicken, 2/3 cat and 2/4 goat is CHICAGO)Ĥ. What is 2/7 chicken, 2/12 Essex warbler and 3/8 terrapin? In a time interval four times longer, the same number of hens will produce four times the number of eggs, so 6 hens lay 24 eggs in 6 days.ģ. If a hen and a half lays an egg and a half in a day and a half, how many eggs do half a dozen hens lay in half a dozen days?Īssuming all hens behave similarly, and egg laying proceeds in linear way, we can state that 1.5 hens lay 1.5 eggs in 1.5 days.įour times the number of hens gives four times the number of eggs in the same time interval, i.e 6 hens lay 6 eggs in 1.5 days.
#CHICKEN MATH IMAGE TRIAL#
Also, in response to the comments below, there are other ways to find the results than by trial and error, but these rely on some technical maths, such as remembering an algorithm, which is beyond the general reader.Ģ. NOTE: There was originally a typo above (as noticed by several readers in the comments). The answer is that you would buy either zero cocks, 25 hens and 75 chicks, OR 4 cocks, 18 hens and 78 chicks, OR 8 cocks, 14 hens and 78 chicks, OR 12 cocks, 4 hens and 84 chicks. In other words we are looking for whole number solutions, and the only way to find them is trial and error. We can assume from the question that since we are dealing in animals, we cannot buy fractions of animals. Substitute that expression for the z in (C) and we get an equation that simplifies to 14 x + 8 y = 200. Multiply (B) by 3 to get (C) 15 x + 9 y + z = 300. If the number of cocks, hens and chicks are x, y and z.
And perhaps this is why there are, in fact, four solutions.) (When the question was set in ancient China they were not able to do this since this technique had not yet been invented. We solve this problem by turning the question into two equations.
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